(3p-3p^-1/3p^-1)^-4

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Solution for (3p-3p^-1/3p^-1)^-4 equation: 


D( p )

p = 0

3*p-(((3*p^-1)/3)*p^-1) = 0

p = 0

p = 0

3*p-(((3*p^-1)/3)*p^-1) = 0

3*p-(((3*p^-1)/3)*p^-1) = 0

3*p-p^-2 = 0

3*p-p^-2 = 0

p*(3-p^-3) = 0

-1*p^-3 = -3 // : -1

p^-3 = 3

-3 < 0

1/(p^3) = 3 // * p^3

1 = 3*p^3 // : 3

1/3 = p^3

p^3 = 1/3 // ^ 1/3

p = (1/3)^(1/3)

p = 0

p = 0

p in (-oo:0) U (0:(1/3)^(1/3)) U ((1/3)^(1/3):+oo)

(3*p-(((3*p^-1)/3)*p^-1))^-4 = 0

(3*p-p^-2)^-4 = 0

1/((3*p-p^-2)^4) = 0

3*p-p^-2 = 0

p*(3-p^-3) = 0

-1*p^-3 = -3 // : -1

p^-3 = 3

-3 < 0

1/(p^3) = 3 // * p^3

1 = 3*p^3 // : 3

1/3 = p^3

p^3 = 1/3 // ^ 1/3

p = (1/3)^(1/3)

p*(p-(1/3)^(1/3)) = 0

1/(p^4*(p-(1/3)^(1/3))^4) = 0

p belongs to the empty set

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